0.3x^2-12x=-112.5

Solution for 0.3x^2-12x=-112.5 equation:

0.3x^2-12x=-112.5

We move all terms to the left:

0.3x^2-12x-(-112.5)=0

We add all the numbers together, and all the variables

0.3x^2-12x+112.5=0

a = 0.3; b = -12; c = +112.5;
Δ = b2-4ac
Δ = -122-4·0.3·112.5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-3}{2*0.3}=\frac{9}{0.6}
=15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+3}{2*0.3}=\frac{15}{0.6}
=25
$